y^2-(p+q)y+pq=0

Solution for y^2-(p+q)y+pq=0 equation:

Simplifying
y2 + -1(p + q) * y + pq = 0

Reorder the terms for easier multiplication:
y2 + -1y(p + q) + pq = 0
y2 + (p * -1y + q * -1y) + pq = 0
y2 + (-1py + -1qy) + pq = 0

Reorder the terms:
pq + -1py + -1qy + y2 = 0

Solving
pq + -1py + -1qy + y2 = 0

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add 'qy' to each side of the equation.
pq + -1py + -1qy + qy + y2 = 0 + qy

Combine like terms: -1qy + qy = 0
pq + -1py + 0 + y2 = 0 + qy
pq + -1py + y2 = 0 + qy
Remove the zero:
pq + -1py + y2 = qy

Add '-1y2' to each side of the equation.
pq + -1py + y2 + -1y2 = qy + -1y2

Combine like terms: y2 + -1y2 = 0
pq + -1py + 0 = qy + -1y2
pq + -1py = qy + -1y2

Reorder the terms:
pq + -1py + -1qy + y2 = qy + -1qy + -1y2 + y2

Combine like terms: qy + -1qy = 0
pq + -1py + -1qy + y2 = 0 + -1y2 + y2
pq + -1py + -1qy + y2 = -1y2 + y2

Combine like terms: -1y2 + y2 = 0
pq + -1py + -1qy + y2 = 0

The solution to this equation could not be determined.